# Description
Person 表:
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
+-------------+---------+
PersonId is the primary key column for this table.
1
2
3
4
5
6
7
8
2
3
4
5
6
7
8
Address 表:
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
+-------------+---------+
AddressId is the primary key column for this table.
1
2
3
4
5
6
7
8
9
2
3
4
5
6
7
8
9
查找 FirstName, LastName, City, State 数据,而不管一个用户有没有填地址信息。
# Solution
涉及到 Person 和 Address 两个表,在对这两个表执行连接操作时,因为要保留 Person 表中的信息,即使在 Address 表中没有关联的信息也要保留。此时可以用左外连接,将 Person 表放在 LEFT JOIN 的左边。
SELECT
FirstName,
LastName,
City,
State
FROM
Person P
LEFT JOIN Address A
ON P.PersonId = A.PersonId;
1
2
3
4
5
6
7
8
9
2
3
4
5
6
7
8
9
# SQL Schema
DROP TABLE
IF
EXISTS Person;
CREATE TABLE Person ( PersonId INT, FirstName VARCHAR ( 255 ), LastName VARCHAR ( 255 ) );
DROP TABLE
IF
EXISTS Address;
CREATE TABLE Address ( AddressId INT, PersonId INT, City VARCHAR ( 255 ), State VARCHAR ( 255 ) );
INSERT INTO Person ( PersonId, LastName, FirstName )
VALUES
( 1, 'Wang', 'Allen' );
INSERT INTO Address ( AddressId, PersonId, City, State )
VALUES
( 1, 2, 'New York City', 'New York' );
1
2
3
4
5
6
7
8
9
10
11
12
13
14
2
3
4
5
6
7
8
9
10
11
12
13
14